Question

find the zero of the following polynomial and verify their relation between their zeros and coefficient
a) t square - 15
b) 4u square + 8u
c) 3x square - x - 4
d) prx square + ( sp +qr)x +qs

Answer 1

Answer:

t^2-15

it can be written as

t^2-(Г15)^2

a2-b2= a+b×a-b

t+Г15and t-Г15

t+Г15=0. and t-Г15=0

t=-Г15. t=Г15

now it should be in standard form

ax^2+bx+c=0

sum of zeros

alpha + beta = -b/a

+Г15-Г15= 0/1

0=0(hece verified)

product of zeros

alpha ×beta= c/a

Г15×Г15=15/1

(Г15)^2=15/1

15=15( hence verified )

the zeros of t^2-15. are 0 and 15

hope it helps you❤