Question

find the zero of the following polynomial p(y)=y^2-13
answer the question correctly plz don't make wromg answers i will give brainliest to the right answer plz write the correct answer ​

Answer 1

Answer:

$\sqrt{13} \: or \: - \sqrt{13}$

Step-by-step explanation:

y²-13=0

y²=13

$y = + \sqrt{13} \: \: \: or \: - \sqrt{13}$