Find the zero of the
polymials x²-3 and verify
the relationship between the zeroes and coefficients,
please say answer fastly
Answers
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Answer:
Given polynomial is x
2
−3
Here, a=1,b=0 and c=−3
x
2
−3=(x−
3
)(x−
3
)
So, the value of x
2
−3 is zero when x=
3
or x=−
3
Threrfore , thr zeroes of x
2
−3 are
3
and −
3
.
Now, sum of zeroes =
3
−
3
=0=
1
0
=
a
−b
product of zeroes =(
3
)(−
3
)=−3=
1
−3
=
a
c
Hence verified
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