Question

find the zero of the polynomail x^2-3

Answer 1

Answer:

x²-3 = 0

x² = 3

x = ±√3

Therefore, the zeroes of the given polynomial are √3 and -√3.

Answer 2

Answer:

answer is -√3 and √3

Step-by-step explanation:

x^2-3

=(x)^2-(√3)^2

=(x+√3)(x-√3). [a^2-b^2=(a+b)(a-b)]

since p(x)=0

(x+√3)(x-√3).=0

x+√3=0 and x-√3=0

x=-√3,√3

Hope it will be helpful.