Math, asked by leothakur1007, 1 year ago

Find the zero of the polynomial 100 x2 - 81

Answers

Answered by sushant2505
10
Hi...☺

Here is your answer...✌

To find zeros,we put

⇒ 100x² - 81 = 0

⇒ (10²)x² - 9² = 0

⇒ (10x)² - (9)² = 0

⇒ (10x + 9) (10x - 9) = 0

⇒ 10x + 9 = 0 or 10x - 9 = 0

⇒ x = -9/10 or x = 9/10

Hence,

zeros of the polynomial 100x² - 81 are -9/10 and 9/10
Answered by Akash1000
0
-9/10 and 9/10

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