Find the zero of the polynomial 100 x2 - 81
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Answered by
10
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Here is your answer...✌
To find zeros,we put
⇒ 100x² - 81 = 0
⇒ (10²)x² - 9² = 0
⇒ (10x)² - (9)² = 0
⇒ (10x + 9) (10x - 9) = 0
⇒ 10x + 9 = 0 or 10x - 9 = 0
⇒ x = -9/10 or x = 9/10
Hence,
zeros of the polynomial 100x² - 81 are -9/10 and 9/10
Here is your answer...✌
To find zeros,we put
⇒ 100x² - 81 = 0
⇒ (10²)x² - 9² = 0
⇒ (10x)² - (9)² = 0
⇒ (10x + 9) (10x - 9) = 0
⇒ 10x + 9 = 0 or 10x - 9 = 0
⇒ x = -9/10 or x = 9/10
Hence,
zeros of the polynomial 100x² - 81 are -9/10 and 9/10
Answered by
0
-9/10 and 9/10
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