find the zero of the polynomial 2x-√3
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Step-by-step explanation:
Given polynomial is 2x3+x2−6x−3
The two roots of polynomial are −3,3
Let the other root be a
Product of the roots will be −2(−3)
⟹(−3)(3)a=23
⟹a=−21
So the other zero is −21
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omkengale:
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