find the zero of the polynomial
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49x² - 64
(7x)² - (8)²
(7x + 8) (7x - 8)
when 7x + 8 = 0 => 7x = -8 => x = -8/7
when 7x - 8 = 0 => 7x = 8 => x = 8/7
Hence.. -8/7 and 8/7 are the zeroes of polynomial.
(7x)² - (8)²
(7x + 8) (7x - 8)
when 7x + 8 = 0 => 7x = -8 => x = -8/7
when 7x - 8 = 0 => 7x = 8 => x = 8/7
Hence.. -8/7 and 8/7 are the zeroes of polynomial.
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Answer:
⇒ x = -8/7 _________(i)
⇒ x = 8/7 _________(ii)
Step-by-step explanation:
Let's factorise the above given terms:
⇒ 49x² - 64
⇒ (7x)² - (8)²
⇒ ( 7x - 8 ) ( 7x + 8 )
Now, we have:
( 7x - 8 ) __________(i)
( 7x + 8 )__________(ii)
Finding zeroes of the polynomial:
⇒ ( 7x - 8 ) = 0
⇒ x = -8/7 _________(i)
Also,
⇒ ( 7x + 8 ) = 0
⇒ x = 8/7 _________(ii)
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