Math, asked by marakroma18otss61, 1 year ago

find the zero of the polynomial

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Answered by Anonymous
1
49x² - 64
(7x)² - (8)²
(7x + 8) (7x - 8)
when 7x + 8 = 0 => 7x = -8 => x = -8/7
when 7x - 8 = 0 => 7x = 8 => x = 8/7
Hence.. -8/7 and 8/7 are the zeroes of polynomial.

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Answered by Anonymous
14

Answer:

⇒ x = -8/7 _________(i)

⇒ x = 8/7 _________(ii)

Step-by-step explanation:

Let's factorise the above given terms:

⇒ 49x² - 64

⇒ (7x)² - (8)²

⇒ ( 7x - 8 ) ( 7x + 8 )

Now, we have:

( 7x - 8 ) __________(i)

( 7x + 8 )__________(ii)

Finding zeroes of the polynomial:

⇒ ( 7x - 8 ) = 0

⇒ x = -8/7 _________(i)

Also,

⇒ ( 7x + 8 ) = 0

⇒ x = 8/7 _________(ii)

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