Question

find the zero of the polynomial 3xraise power 2 - 1 plzz answer quickly​

Answer 1

$\bold\red{\underline{\underline{Answer:}}}$

$\bold{Roots \ are \ \frac{-1}{\sqrt3} \ and \ \frac{1}{\sqrt3}}$

$\bold\orange{Given:}$

$\bold{The \ given \ polynomial \ is}$

$\bold{=>3x^{2}-1}$

$\bold\pink{To \ find:}$

$\bold{Roots \ of \ the \ polynomial.}$

$\bold\green{\underline{\underline{Solution}}}$

$\bold{=>3x^{2}-1}$

$\bold{=>(\sqrt3x)^{2}-1}$

$\bold{By \ identity \ a^{2}-b^{2}=(a+b)(a-b)}$

$\bold{=>(\sqrt3x+1)(\sqrt3-1)}$

$\bold{=>x=\frac{-1}{\sqrt3} \ or \ \frac{1}{\sqrt3}}$

$\bold\purple{\therefore{Roots \ are \ \frac{-1}{\sqrt3} \ and \ \frac{1}{\sqrt3}}}$