Question

Find the zero of the polynomial 4s²-4s+1 and verify the relationship between the zeros and the coefficient​

Answer 1

$\huge \fbox \blue{Answer:}$

$→ {45}^{2} - 45 + 1 = 0$

$∴ {45}^{2} - 25 - 25 + 1 = 0$

$∴25(25 - 1) - 1(25 - 1) = 0$

$⇒(25 - 1)(25 - 1) = 0$

$⇒s = +1 /2$

$⇒ \textbf{sum \: of \: roots} = \frac{1}{2} + \frac{1}{2} = 1...(1)$

$⇒ \textbf{sum \: of \: roots \: verified} = \frac{ - b}{a} = \frac{ - (4)}{4} = 1...(2)$

$\textbf{also \: product \: of \: roots} = \frac{c}{a} = \frac{1}{4}$

$\textbf{Also} \: \left( \frac{1}{2} \right) \]\left( \frac{1}{2} \right) \] = \frac{1}{4}$

$\\ \\ \\ \\ \\ \\ \sf \colorbox{gold} {\red(ANSWER ᵇʸ ⁿᵃʷᵃᵇ⁰⁰⁰⁸}$

Answer 2

Answer:

Step-by-step explanation: