Question

find the zero of the polynomial 4u square + 8u

Answer 1

The equation is 4u2+8u

Taking 4u common

4u(u+2)=0
U+2=0
U=-2.

Hope it helps

Answer 2

Answer:

0, -2 are two zeroes of given polynomial.

Step-by-step explanation:

Let p(u)=4u²+8u

To find zero of the polyomial ,

we must take p(u)=0

=> 4u²+8u=0

=> 4u(u+2)=0

=> 4u=0 Or u+2=0

=> u=0 Or u = -2

Therefore,

0, -2 are two zeroes of given polynomial.

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