Question

find the zero of the polynomial 4xsquare-9

Answer 1

4×ssquare-9=0
4×s square=9
s square=9/4
s=√ 9/4
s=+-3/2

Answer 2

Heya.

Given Polynomial :-

4x² - 9 = 0.

We have to obtain the zeroes of the polynomial :-

Transposing 9 to RHS :-
4x² = 9
$x^{2} = \frac{9}{4} \\ x=+- \sqrt{ \frac{9}{4}} \\ x=\sqrt{ \frac{9}{4}} or x=-\sqrt{ \frac{9}{4}} \\ x = \frac{3}{2} or x = -\frac{3}{2}$

Hence, the two roots of given polynomial are -3/2 and 3/2.

 Hope it helps..