find the zero of the polynomial 5 x square + 2 x minus 8
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Answered by
3
Hey mate!
Here's your answer!!
5x² + 2 × -8
The first term is, 5x2 its coefficient is 5 .
The middle term is, +2x its coefficient is 2 .
The last term, "the constant", is -8.
5 × -8 = -40
Find two factors of -40 whose sum equals the coefficient of the middle term, which is 2 .
40 + 1 = -39
-20 + 2 = -18
-10 + 4 = -6
-8 + 5 = -3
-5 + 8 = 3
-4 + 10 = 6
-2 + 20 = 18
-1 + 40 = 39
Conclusion : Trinomial can not be factored.
✌ ✌
Here's your answer!!
5x² + 2 × -8
The first term is, 5x2 its coefficient is 5 .
The middle term is, +2x its coefficient is 2 .
The last term, "the constant", is -8.
5 × -8 = -40
Find two factors of -40 whose sum equals the coefficient of the middle term, which is 2 .
40 + 1 = -39
-20 + 2 = -18
-10 + 4 = -6
-8 + 5 = -3
-5 + 8 = 3
-4 + 10 = 6
-2 + 20 = 18
-1 + 40 = 39
Conclusion : Trinomial can not be factored.
✌ ✌
Answered by
11
HEY....☺
Here's ur ans. ⬇
_______________________
Zeroes of the polynomial ⤵
5x^2 + 2x - 8
alpha × beeta = c/a = -8/5
alpha + beeta = -b/a = -2/5
Here , a is the coefficient of x^2 , b is the coefficient of x and c is constant.
Since , it's polynomial instead of quadratic , there are infinite zeroes of it .
_________________________
✌Hope it helps
Here's ur ans. ⬇
_______________________
Zeroes of the polynomial ⤵
5x^2 + 2x - 8
alpha × beeta = c/a = -8/5
alpha + beeta = -b/a = -2/5
Here , a is the coefficient of x^2 , b is the coefficient of x and c is constant.
Since , it's polynomial instead of quadratic , there are infinite zeroes of it .
_________________________
✌Hope it helps
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