Question

find the zero of the polynomial 9x square -3x-20 and verify the relationship between the zeroes and the cofficient​

Answer 1

Answer:

Step-by-step explanation:

X = -4/3,5/3

Answer 2

Answer:

9x²-3x-20=0

x = -b±√b²- 4ac/2a

x = -(-3)±√(-3)²-4(9)-20/2(9)

x = 3±√9 + 720/18

x = 3 ± √729/18

x = 3 ± 27/18

x = 3 + 27/18 x = 3-27/18

x = 30/18 x = -24/18

x = 5/3 x = -4/3

alpa= 5/3 ,beta = -4/3

alpa+ beta = -b/a

5/3+(-4/3) = -(-3)/9

5 - 4/3 = 3/9

1/3 = 1/3

alpa(beta) = c/a

5/3(-4/3) = -20/9

-20/9 = -20/9

I hope this answer will help you mate!☺️