Question

Find the zero of the polynomial given below x²+4x+4 and x²-7x+10

Answer 1

$\fbox{\texttt{\green{Answer:}}}$

Zeroes of the polynomial x² + 4x + 4 = -2 & -2

Zeroes of the polynomial x² - 7x + 10 = 5 & 2

$\fbox{\texttt{\pink{Given:}}}$

Polynomial p(x) = x² + 4x + 4

Polynomial f(x) = x² - 7x + 10

$\fbox{\texttt{\blue{To\:find:}}}$

Zeroes of the polynomials p(x) and f(x).

$\fbox{\texttt{\red{How\:to\:Find:}}}$

p(x) = x² + 4x + 4

Now, x² + 4x + 4 = 0

By splitting the middle term, we get,

⇝ x² + 2x + 2x + 4 = 0

⇝ x(x + 2) + 2(x + 2) = 0

⇝ (x + 2)(x + 2) =0

⇝ x = -2, -2

Therefore, the zeroes of the polynomial p(x) = -2 & -2.

$\rule{200}3$

f(x) = x² - 7x + 10

Now, x² - 7x + 10 = 0

By splitting the middle term, we get,

⇝ x² - 2x - 5x + 10 =0

⇝ x(x - 2) - 5(x - 2) =0

⇝ (x - 5)(x - 2) = 0

⇝ x = 5, 2

Therefore, zeroes of the polynomial f(x) = 5 & 2.