Question

find the zero of the polynomial
(i) 24p2 – 41p + 2

Answer 1

Answer:

24p^2-41p+2

24p^2-9p-32p+12

3p(8p-3) -4(8p-3)

(8p-3) (3p-4)

8p-3=0, 3p-4=0

therefore, p=3/8, p=4/3

hence, found