Find the zero of the polynomial: (i)P(x)x++3
(ii)P(x) =(x+1)(x+2)
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i)-3
ii)-2
these are my answers
hope it helps
tag as the brainliest
ii)-2
these are my answers
hope it helps
tag as the brainliest
Kichu32:
can u make it long
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Hi friend,
(i)p(x) =x+3
p(x)=0
x+3=0
x= -3
Therefore, -3 is the zero of the polynomial x+3.
(ii) p(x)=(x+1)(x+2)
p(x)=0
(x+1)(x+2)=0
x+1=0 ; x= -1
x+2=0 ; x= -2
Therefore, -1 and -2 are zeroes of the polynomial (x+1)(x+2)
Hope it helps..
(i)p(x) =x+3
p(x)=0
x+3=0
x= -3
Therefore, -3 is the zero of the polynomial x+3.
(ii) p(x)=(x+1)(x+2)
p(x)=0
(x+1)(x+2)=0
x+1=0 ; x= -1
x+2=0 ; x= -2
Therefore, -1 and -2 are zeroes of the polynomial (x+1)(x+2)
Hope it helps..
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