Question

find the zero of the polynomial
(I)
${x}^{2} - 2x - 3$
​

Answer 1

Question:-

Find the zero of polynomial:-

${x}^{2}-2x-3$

Answer:-

$\implies$ ${x}^{2}-2x-3$

By splitting ${x}^{2}$ and $-3$ we get, $-3x$ and $x$

$\implies$ ${x}^{2}+x-3x-3$

$\implies$ $({x}^{2}+x)+(-3x-3)$

$\implies$ $x(x+1)-3(x+1)$

$\implies$ $(x-3)(x+1)$

Now,

$x-3=0$ $\: \: \:$ $\: \: \:$ and $\: \: \:$ $x+1=0$

$\large{x=3}$ $\: \: \:$ $\: \: \:$ and $\: \: \:$ $\large{x=-1}$

$\therefore$ zeroes of given polynomial are $3$ and $-1$

$\underline\color{green}\boxed{x=3 \: and \: -1}$

Answer 2

Answer:

As its name implies, radioactivity is the act of emitting radiation spontaneously. This is done by an atomic nucleus that, for some reason, is unstable; it "wants" to give up some energy in order to shift to a more stable configuration.As its name implies, radioactivity is the act of emitting radiation spontaneously. This is done by an atomic nucleus that, for some reason, is unstable; it "wants" to give up some energy in order to shift to a more stable configuration.