find the zero of the polynomial in each case :-
p (x) = x + 5
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Answered by
44
Answer:
) x+5=0x=-5(zero)ii) x-5=0x= 5(zero)iii) 2x+5=0x=-5/2(zero)IV) 3x-2=0x= 2/3( zero)v) 3x=0x=0(zero)vi) ax=0x=0(zero)vii) ...
Answered by
10
Answer:
P(x) = x + 5
x = –5
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