Find the zero of the polynomial in each of the following cases:
(I) p(x)=x +5
(ii) p(x)=x-5
(iii) p(x) = 2x + 5
(iv) p(x) = 3x - 2
(v) p(x) = 3x
(vi) p(x) = ax, a 70
(vii) p(x) = cx +d, c#0, c, d are real numbers.
Answers
Answered by
10
Answer:
- p (x)= x +5 = 0
x = 0 - 5
x = - 5
2. p(x )= x - 5 = 0
x = 0 + 5
x = 5
3. p(x) = 2x + 5 = 0
2x = 0 - 5
2x = - 5
x = - 5/ 2
4. p(x) = 3x - 2 = 0
3x = 0 + 2
3x = 2
x = 3/2
Answered by
1
Answer:
1)-5 2)5 3)-5/2 4)2/3
Step-by-step explanation:
1)p(-5)=0
- 5is zero of p(x) 2)p(5)=0. 5is zero of p(x). 3)p(x)=0 ;2x+5=0 2x=-5 x=-5/2 4)p(x)=0;3x-2=0 3x=2 x=2/3
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