Math, asked by Arsin11, 1 year ago

Find the zero of the polynomial in each of the following cases:
(I) p(x)=x +5
(ii) p(x)=x-5
(iii) p(x) = 2x + 5
(iv) p(x) = 3x - 2
(v) p(x) = 3x
(vi) p(x) = ax, a 70
(vii) p(x) = cx +d, c#0, c, d are real numbers.​

Answers

Answered by nitu171
10

Answer:

  1. p (x)= x +5 = 0

x = 0 - 5

x = - 5

2. p(x )= x - 5 = 0

x = 0 + 5

x = 5

3. p(x) = 2x + 5 = 0

2x = 0 - 5

2x = - 5

x = - 5/ 2

4. p(x) = 3x - 2 = 0

3x = 0 + 2

3x = 2

x = 3/2

Answered by padmaja89
1

Answer:

1)-5 2)5 3)-5/2 4)2/3

Step-by-step explanation:

1)p(-5)=0

- 5is zero of p(x) 2)p(5)=0. 5is zero of p(x). 3)p(x)=0 ;2x+5=0 2x=-5 x=-5/2 4)p(x)=0;3x-2=0 3x=2 x=2/3

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