Math, asked by snehaldk, 7 months ago


Find the zero of the polynomial in each of the following cases:
(i) p(x) = x +5
(ii) p(x) = x-5
(iii) p(x) = 2x + 5
(iv) p(x) = 3x-2
(v) p(x)= 3x
(vi) p(x) = ax, a=0
(vii) p(x) = cx +d, c#0, c, d are real numbers.​

Answers

Answered by SaumyadityaNath
0

Answer:

1. -5

2. 5

3. -5÷2

4. 2÷3

5. 0

6. any number

7. -d÷c

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Answered by MekhaSaji
2

Answer:

(i) x + 5 =0

x= -5

(ii) x - 5 = 0

x=-5

(iii) 2x + 5 = 0

2x = -5

x = -5/2

(iv) 3x - 2 = 0

3x = -2

x = -2/3

(v) 3x = 0

x = -3

(vi) any real number

(vii) -d/c

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