Find the zero of the polynomial in each of the following cases:
(1) P(x)=x+5
(ii) p(x)= x-5
(iii) p(x) = 2x+5
(iv) p(x) = 3x-2
(v) p(x)= 3x
(vi) p(x) = ax, a
(vii) p(x) = cx+d, c#0, c, d are real numbers.
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P(x) =x+5 is correct answer please mark me brainlest and follow me
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To find zero of the polynomial, p(x)=0
(i) If p(x)=x+5=0 then x=−5, i.e. −5 is the zero.
(ii) If p(x)=x−5=0 then x=5, i.e. 5 is the zero.
(iii) If p(x)=2x+5=0 then x=−5/2, i.e. −5/2 is the zero.
(iv) If p(x)=3x−2=0 then x=⅔, i.e. ⅔ is the zero.
(v) If p(x)=3x=0 then x=0, i.e. 0 is the zero.
(vi) If p(x)=ax=0 then x=0, i.e. 0 is the zero.
(vii) If p(x)=cx+d=0 then x=−d/c, i.e. −d/c is the zero.
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