Question

Find the zero of the polynomial in each of the following=
P(x)=x^2+5x-6

Answer 1

Answer:

Step-by-step explanation:

(x+6)(x-1)

X=-6,X=1

Answer 2

Answer:

$\huge{\boxed{\boxed{\sf{x=-6\:and\:1}}}}$

Step-by-step explanation:

$\huge{\boxed{\boxed{\underline{\sf{SOLUTION}}}}}$

$\huge{\boxed{\boxed{\underline{\sf{1st\:METHOD}}}}}$

$= ) {x}^{2} + 5x - 6 = 0 \\ = ) {x}^{2} + 6x - x - 6 = 0 \\ = ) x(x + 6) - 1(x + 6) = 0 \\ = )(x - 1)(x + 6) = 0 \\ = )x - 1 = 0 \\ = ) x = 1 - - - - - 1st \: zeroes \\ = )x + 6 = 0 \\ = ) x = - 6 - - - - - 2nd \: zeroes$

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$\huge{\boxed{\boxed{\underline{\sf{2nd\:METHOD}}}}}$

${x}^{2} + 5x - 6 \\ d = {b}^{2} - 4ac \\ d = {5}^{2} - 4(1 \times - 6) \\ d = 25 + 24 \\ d = 7 \\ again \\x = \frac{ - b + \sqrt{d} }{2a} \\ x = \frac{ - 5 + 7}{2} \\ x = \frac{2}{2} \\ x = 1 - - - - - 1st \: zeroes \\ x = \frac{ - b - \sqrt{d} }{2a} \\ x = \frac{ - 5 - 7}{2} \\ x = \frac{ - 12}{2} \\ x = - 6 - - - - - 2nd \: zeroes$

$\huge{\boxed{\boxed{\sf{x=-6\:and\:1}}}}$

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