Question

Find the zero of the polynomial of p(y)=y2-1

Answer 1

Answer:

to find zeroes,

p(y) = 0

=> y² -1 = 0

=> y² = 1

=> y = √1

=> y = ± 1

so,

the zeroes of p(y) are 1 and -1.

$.$

Answer 2

Answer:

$zeros \: of \: polynomial \: of \: p(y) = {y}^{2} - 1 \\ \\ \\ \implies {y}^{2} - 1 = 0 \\ \\ \\ \implies {y}^{2} = 1 \\ \\ \\ \implies \: y =\sqrt{1} \\ \\ \\ \implies \: y = + 1 \: and \: - 1 \\ \\ \\so \: zeros \: of \: polynomial \: p(y) = + 1,- 1$