find the zero of the polynomial P of X is equals to 6 x square - 3 - 7x
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put ( x) = 6 so, (6) ^2-3-7x6
36-45
-9
yashas88:
no its not right ga.....d
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6x^2-7x-3=0
6x^2-(9-2)x-3=0
(6x^2-9x)+(2x-3)=0
3x(2x-3)+1(2x-3)=0
(3x+1)(2x-3)=0
3x+1=0 or 2x-3=0
x=-1/3 or x=3/2
hope it will help
pls mark as brainlist
6x^2-(9-2)x-3=0
(6x^2-9x)+(2x-3)=0
3x(2x-3)+1(2x-3)=0
(3x+1)(2x-3)=0
3x+1=0 or 2x-3=0
x=-1/3 or x=3/2
hope it will help
pls mark as brainlist
Pls mark as brianlist I will be very thankful to u
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