Question

Find the zero of the polynomial  P(t) = (t+1)^2- (t-1)^2​

Answer 1

If t=1 is the zero of the polynomial, then p(t)=0. To verify this, find value of p(t)

p(t)=2t

3

−3t

2

+7t−6

p(1)=2(1)

3

−3(1)

2

+7(1)−6

=2−3+7−6=0

∴t=1 is a zero of the given polynomial.

Answer 2

Answer:

Given:—

$P(t) = (t+1)^2- (t-1)^2$

$\: \: \: = ( t + 1 + t -1) ( t+1 - t +1)$

$\: \: \: = 2t × 2$

$\: \: \: \: = 4t$

$\bold{So, \: \: \: { \underline{P(t) \: = \: 4t}}}$

Now, P(t) will be '0' when ,

$\bold{4t = 0}$

$\implies \: t \: = 0$

$\bold{ \mathtt{ \color{red}{ Hence , \: the \: zero \: of \: the \: polynomial \: is \implies 0}}}$