Question

find the zero of the polynomial p[x]=5z[x+2] [x-2]

Answer 1

Hi there!

♦ Given :-
p(x) = (x - 2)² - (x + 2)²

Therefore, (x - 2)² - (x + 2)² = 0. ----[ a² - b² = (a - b)(a + b) ]

[ x - 2 - (x + 2) ] ( x - 2 + x + 2 ) = 0

(x - 2 - x - 2) (2x) = 0

(-4) (2x) = 0

2x = 0 / -4

2x = 0

x = 0 / 2

x = 0

Hence, The required answer is :-
The Zero of the polynomial is 0.

hope it helps! :)

Answer 2

Step-by-step explanation:

Hi friend,

Your question might be as follows:-

Find the zero of the polynomial p(x) = 5x{x+2}{x-2}

==========================

p(x) = 0

5x(x+2)(x-2) = 0

5x = 0 ; x = 0

x+2 = 0 ; x = -2

x-2 = 0 ; x = 2

Therefore,the zeroes of the given polynomial are 0,2 and -2.

Hope it helps