find the zero of the polynomial p(x)= 6x^2+7x-3
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SOLUTION :
Given : polynomial 6x² + 7x - 3
=6x² - 2x + 9x - 3
[By splitting the middle term]
=2x(3x - 1) +3(3x - 1)
=(2x + 3)(3x - 1)
(2x + 3)(3x - 1) = 0
⇒2x + 3 = 0 or 3x - 1=0
⇒x = -3/2 or x= ⅓
Hence , the Zeroes of the Polynomial are -3/2 & ⅓.
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