Find the zero of the polynomial p ( x) = 6xsquare+7x-3
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Answer:
x = -3/2 x = 1/3
Step-by-step explanation:
p(x) = 6x² + 7x - 3
Splitting middle terms
6x² + 9x - 2x -3 [∵ 9×(-2) = -18 and 9 - 2 = 7]
taking 3x common from first two terms and -1 from last two terms
3x ( 2x + 3) -1 (2x + 3)
(2x + 3) ( 3x - 1)
To find zero
2x + 3 = 0 3x - 1 = 0
x = -3/2 x = 1/3
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