find the zero of the polynomial p(x)=9x²-4a²
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Answer:
p(x)=9x²-4a²
=(3x)²-(2a)²
=(3x+2a)(3x-2a)
taking p(x)=0
(3x+2a)(3x-2a)=0
3x+2a=0, 3x-2a=0
x=2a/3, x= -2a/3
so,2a/3 and -2a/3 are the zeroes of the given polynomial
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