Question

find the zero of the polynomial
p(X)=(X+1) (X+2)​

Answer 1

Answer:

x=-1 and

x=-2

We put x+1=0

x=-1

and

x+2=0

x=-2

so zero of the polynomial is -1 and -2

Answer 2

$p(x+1)$

$p(x)=0$

$x+1=0$

$x=-1$

$&#8756$$zero=-1$

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$p(x+2)$

$p=0$

$x+2=0$

$x=-2$

$&#8756$$zero=-2$