Question

Find the zero of the polynomial p(x)=(x-2)^2-(x+2)^2

Answer 1

Answer:

Step-by-step explanation:

(a+b)(a-b) = a^2-b^2

(x-2)^2-(x+2)^2=0

(x-2+x+2)(x-2-x-2)=0

2x * -4=0

x=0

The root of given polynomial is 0

Hope it helps

..........................

Answer 2

Step-by-step explanation:

Given:

p(x) = (x - 2)² - (x + 2)²

To find:

zeroes of the polynomial.

Solution:

We have

p(x) = (x - 2)² - (x + 2)²

Finding a zero of the polynomial, is the same as solving the equation p(x) = 0, we get

(x - 2 + x + 2)(x - 2 - x - 2) = 0

⇒ (2x) (-4) = 0

⇒-8x = 0

⇒x = 0

Hence, 0 is a zero of the polynomial p(x) = (x - 2)² - (x + 2)²