find the zero of the polynomial p(x)=(x-2)²-(x+2)².
Answers
Answered by
0
Answer:
P(x)=(x−2)
2
−(x−2)
2
This is in the form of a
2
−b
2
P(x)=(x−2+x+2)(x−2−(x+2))
P(x)=2x(x−2−x−2)
P(x)=2x(−4)
P(x)=0
−8x=0
x=0
Hence,
x=0 is the zero of the polynomial P(x)
Answered by
0
Answer:
P(x)=(x−2)
2
−(x−2)
2
This is in the form of a
2
−b
2
P(x)=(x−2+x+2)(x−2−(x+2))
P(x)=2x(x−2−x−2)
P(x)=2x(−4)
P(x)=0
−8x=0
x=0
Hence,
x=0 is the zero of the polynomial P(x)
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