Question

Find The Zero Of The Polynomial p(x) =x^2+9x+20​

Answer 1

Answer:

zeroes of the polynomial are -4 and -5

Step-by-step explanation:

x² + 9x + 20 = 0

x² + 4x + 5x + 20 = 0

x(x+4) + 5(x+4) = 0

(x+4) (x+5) = 0

x+4 = 0 | x+5 = 0

x = -4 | x = -5

so ,the zeroes of the polynomial are -4 and -5.

Answer 2

$\huge{\bf{\underline{\underline{\pink{Question}}}}}$

${x}^{2} + 9x + 20$

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$solving \: by \: prime \: factorization \\ method : \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \:$

${x}^{2} + 9x + 20$

$\implies{x}^{2} + 4x + 5x + 20$

$\implies \: x(x + 4) + 5(x + 4)$

$\implies(x + 4)(x + 5)$

$either,\implies \: x = - 4 \: or \: x = - 5$

$\huge{\bf{\underline{\underline{\pink{hope \: its \: help \: u }}}}}$