Question

find the zero of the polynomial p (x) = {( x-2) + (x+2)} - {(x-2) - (x+2)}​

Answer 1

Answer:

0 IS THE ZERO OF _______

Step-by-step explanation:

Answer 2

Answer:

P(x)=(x−2)

2

−(x−2)

2

This is in the form of a

2

−b

2

P(x)=(x−2+x+2)(x−2−(x+2))

P(x)=2x(x−2−x−2)

P(x)=2x(−4)

P(x)=0

−8x=0

x=0

Hence,

x=0 is the zero of the polynomial P(x)

OR

Given, polynomial is p(x) = (x – 2)2 – (x+ 2)2

For zeroes of polynomial, put p(x) = 0

(x – 2)2 – (x+ 2)2 = 0

(x-2 + x+2)(x-2-x-2) = 0 [using identity, a2-b2 =(a-b)(a + b)] ⇒ (2x)(-4) = 0