find the zero of the polynomial p(x)=(x-4)^2-(x-6)^2
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Answered by
3
p(x) = (x^2+16-8x )-(x^2+36-12x)
= -20+4x
-4x = -20
x = 5
Answered by
1
Answer:
(x-4)²-(x-6)²
x²+8x-16-x²+12x-36
20x-52
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