find the zero of the polynomial:
p(y)=3y/7+6
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Step-by-step explanation:
let p(x) = 3y/7 + 6 = 0
3y /7 +6 = 0
3 y = -6 ×7
y = (-6×7)/3
y = -2 × 7
y = - 14
I m not sure about the steps but may the ans is correct pls verify and write
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