Question

Find the zero of the polynomial P(y)=ycube/27-1

Answer 1

Answer:

Step-by-step explanation:

f(y)=y³/27-1

27(f(y))=y³-27

=y³-3³

=(y-3)(y²+3y+9)

so y-3=0,y=3

and y²+3y+9=0

y=[-3±√(9-36)]/2

=(-3±√-27)/2

= (-3±3√-3)/2

=-3/2*(1±√-1)

Hence the roots are 3 and -3/2*(1±√-1)