Question

find the zero of the polynomial px=2x +1 and p(x) =x2 -4​

Answer 1

Answer:

If you divide 7/3, you get 2 as quotient, 1 as remainder. Also 3 is divisor here & 7 is dividend.

So we can write 7 = (3 * 2) +1 or Dividend = (Divisor * Quotient) + Remainder.

Observe that Remainder is always less that Divisor.

Let’s try to divide two polynomials. E.g. p(x)/ q(x) where p(x) = 2x3 + x2 + x & q(x) =x.

In this case , x is common to each term of 2x3 + x2 + x. So we can write 2x3 + x2 + x as x(2x2 + x + 1). We say that x and 2x2 + x + 1 are factors of 2x3 + x2 + x, and 2x3 + x2 + x is a multiple of x as well as a multiple of 2x2 + x + 1.

Let us try to divided p(x)= 3x2 + x + 1 with q(x)= x.