find the zero of the polynomial q(t)=(t+1)2-(t-1)2
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Answer:
If (2t+1)is a factor then t=
2
−1
must be one of the zeroes of the given polynomial. Substituting in the given equation.
q((
2
−1
))=4(
2
−1
)
3
+4(
2
−1
)
2
−(
2
−1
)−1
=4(
8
−1
)+4(
4
1
)+(
2
1
)−1
=(
2
−1
)+1+(
2
1
)−1=0
Hence(2t+1) is a common factor of q(t)
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