Question

find the zero of the polynomial
$4s ^{2} - 4s + 1$
if u answer it correctly (with each and every steps) ,
I will mark u as the BRAINLIEST...​

Answer 1

p(x) = 4s² - 4s + 1

☛ 4s² - 2s - 2s + 1

☛ 2s ( 2s - 1 ) - 1 ( 2s - 1 )

☛ (2s - 1)(2s - 1)

2s - 1 = 0 or 2s - 1 = 0

s = 1/2

Hence, Zero of the polynomial is 1/2

Answer 2

$\huge{\underline{\underline{\mathcal{\pink{ANSWER}}}}}$

Answer:

s=1/2,1/2

Step-by-step explanation:

${4s}^{2} - 4s + 1$

${4s}^{2} - 2s - 2s + 1$

$2s(2s - 1) - 1(2s - 1)$

$(2s - 1)(2s - 1)$

for zeroes

2s-1=0

2s=1

$s = \frac{1}{2}$

hence required 0s are

$s = \frac{1}{2} and \: s = \frac{1}{2}$

HOPE IT HELPS YOU

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