Question

Find the zero of the polynomial
$p(y) = \frac{y { }^{3} }{27 \: } \: - 1$
​

Answer 1

Answer:

the zero of the polynomial

$p(y) = \frac{y { }^{3} }{27 \: } \: - 1$

is

Step-by-step explanation:

(y/3-1) (y^2/9+y/3+1)