Question

find the zero of the polynomial
$x {}^{2} - 2x - 8$
​

Answer 1

Answer:

the zero of polynomial is -2,4

Step-by-step explanation:

x^2-2x-8

=x^2-4x+2x-8

=x(x-4)+2(x-4)

=(x-4)(x+2)

=x =4,-2

Answer 2

GIVEN :

Polynomial : x² - 2x - 8

We can find the zeroes of Polynomial by splitting the middle terms

x² - 2x - 8

x² - 4x + 2x - 8

x(x - 4) + 2(x - 4)

x - 4 = 0 and x + 2 = 0

x = 4 and x = -2 are the zeroes of Polynomial.

VERIFICATION :

p(4) = x² - 2x - 8

= (4)² - 2(4) - 8

= 16 - 8 - 8

= 16 - 16

= 0

p(-2) = x² - 2x - 8

= (-2)² - 2(-2) - 8

= 4 + 4 - 8

= 8 - 8

= 0

Therefore, 4 and -2 are the zeroes of Polynomial.