Question

find the zero of the polynomial x^2+3/2 root 5x.-5
plz very urgent plz help​

Answer 1

Answer:

Given :   polynomial  x² + 3√5/2 x  - 5  

To find : the zeroes of the polynomial

Solution:

x² + 3√5/2 x  - 5  

= x²   +2√5x  - √5 / 2 x  -  5

= x(x + 2√5)  - (√5 / 2 ) (x +  2√5)

= (x  - √5 / 2)(x + 2√5)

zeroes are

√5 / 2  , -  2√5

Sum of Zeroes = √5 / 2   -   2√5   = - 3√5/2

Product of Zeroes =  (√5 / 2)(-2√5)  =   -5

for ax² + bx + c

Sum of Zeroes = -b/a

Product of Zeroes = c/a

here a = 1   b = √5 / 2  c =  -5

Sum of  Zeroes  = -  3√5/2

Product of Zeroes  = -5

Answer 2

solution: X² 2+3√5/2X-5=0

= X² 2+2√5X-√5/2x-5

= x(x+2√5) -(√5/2) (x+2√5)

= (x-√5/2) ( x+2√5)

= √5/2, -2√5

verification:

=√5/2-2√5=3√5/2

=(√5/2) (-2√5)=-5

for ax²+bx+c

= -b/a

=c/a

a=1 , b=√5/2. c=-5

=3√5/2

=-5 Ans