find the zero of the polynomial x 2 power -12+35
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Answered by
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Hey !!
x² - 12x + 35 =0
=> x² - 7x - 5x + 35 [=0by using spliting method of quadratic equation?
=> x ( x - 7) -5(x - 7) =0
=> (x -5)(x -7) =0
x - 5 = 0
x = 5
and 2nd zeeo is
x -7 =0
x =7
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Hope it helps you !!!
@Rajukumar111
x² - 12x + 35 =0
=> x² - 7x - 5x + 35 [=0by using spliting method of quadratic equation?
=> x ( x - 7) -5(x - 7) =0
=> (x -5)(x -7) =0
x - 5 = 0
x = 5
and 2nd zeeo is
x -7 =0
x =7
************************
Hope it helps you !!!
@Rajukumar111
Answered by
0
Hii friend,
X²-12X+35
X² - 7X -5X + 35
X(X-7) -5 ( X-7)
(X-7) (X-5)
(X-7) = 0. OR (X-5) = 0
X = 7. OR X = 5
Hence,
7 and 5 are the zeros of the polynomial.
HOPE IT HELPS!!!
X²-12X+35
X² - 7X -5X + 35
X(X-7) -5 ( X-7)
(X-7) (X-5)
(X-7) = 0. OR (X-5) = 0
X = 7. OR X = 5
Hence,
7 and 5 are the zeros of the polynomial.
HOPE IT HELPS!!!
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