Question

find the zero of the polynomial x^2+x-p(p+1).

Answer 1

Heya Dear ,,,,

Solution is here ⬇⬇

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f (x) = x^2 + x - p (p+1)
by adding and subtracting p x , we get

$f(x) = {x}^{2} + px + x - px - p(p + 1) \\ = > {x}^{2} + (p + 1)x - px - p(p + 1) \\ = > x(x + p + 1) - p(x + p + 1) \\ = > (x + (p + 1))(x - p)$
=> f (x) =0

=> [x+( p+1 ) ] (x - p )=0

=> [x + (p + 1 )] =0 or (x - p)=0

=> x = -(p+1) or x = p

so, the zeroes of f(x) are -(p+1) and p

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Hope it's helps you.
☺☺✌✌

Answer 2

Refers to attachment!!

hope IT HELPs!!