find the zero of the polynomial x²-16x
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Answered by
1
Answer:
x²-16x
x(x-16)
x=0
x-16=0
x=16
therefore, zeroes are 0 & 16
Answered by
0
P(x)= x^2- 16x
P(0)= 0^2 -16*0
= 0- 0 =0
P(0)= 0^2 -16*0
= 0- 0 =0
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