Find the zero of the polynomial x²-2x-8
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Answer:
Here is your answer
Step-by-step explanation:
Given
P(x) = x^2 - 2x - 8
Solution
x = -2
P(-2) = 4 + 4 - 8
Remainder = 0
So, the zero of the polynomial is -2 and factor is x + 2
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