find the zero of the polynomial x²+3x-10 and verify the relationships between the zeros and the coefficient.
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Answer:
x²-2x+5x-10
x(x-2) +5( x-2)
(x+5) (x-2)
so, zeros are:-
x+5=0
x=0-5= -5,
x-2=0
x=0+2=2
sum of zeros: -5+2= -3
coefficient of zeros -5×2=10
verify:- [a=1,b=3,c=-10]
sum of zeros:- -b/a = -3/1= -3
coefficient of zeros:- c/a= -10/1= -10
proved.
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