Math, asked by sureshrao99, 11 months ago

Find
the
zero of the
polynomial x²+x+6​

Answers

Answered by Anonymous
2

Answer:-3,-2

pls refer my attachment:

hope it helps✌✌

Attachments:
Answered by Anonymous
1

\Large{\underline{\underline{\bf{Solution :}}}}

We know that,

\large{\implies{\boxed{\boxed{\sf{x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} }}}}}

Where,

a = 1

b = 1

c = -6

_______________[Put Values]

\sf{→x = \frac{-1 \pm \sqrt{1^2 - 4(1)(-6)}}{2(1)}} \\ \\ \sf{→x = \frac{1 \pm \sqrt{1 + 25}}{2}} \\ \\ \sf{→x = \frac{1 \pm \sqrt{1 + 24}}{2}} \\ \\ \sf{x = \frac{1\pm 5}{2}}

\rule{150}{2}

When +

\sf{→x = \frac{1 + 5}{2}} \\ \\ \sf{→x = \frac{\cancel{6}}{\cancel{2}}} \\ \\ \sf{→x = 3}

\rule{150}{2}

When -

\sf{→x = \frac{1 - 5}{2}} \\ \\ \sf{→ x = \frac{\cancel{-4}}{\cancel{2}}} \\ \\ \sf{→x = -2}

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