Question

find the zero of the polynomial z square minus 2 ​

Answer 1

Answer:

z = $\sqrt{2}$

Step-by-step explanation:

$z^{2} - 2 = 0\\z^{2} + 0z -2 = 0\\Here \ a = 1, b = 0, c = -2\\Using \ Quadratic \ Formula\\z = \frac{-b + \sqrt{b^{2} - 4ac}}{2a} \ and \ z = \frac{-b - \sqrt{b^{2} - 4ac}}{2a}\\\\z = \frac{0 \ + \sqrt{0^{2} - 4*1*-2}}{2*1} \ and \ z = \frac{0 \ - \sqrt{0^{2} - 4*1*-2}}{2*1}\\\\z = \frac{\sqrt{8}}{2} \ and \ z =\frac{\sqrt{8}}{2} \\\\z = \frac{\sqrt{8}}{2} = \frac{2\sqrt{2}}{2} = \sqrt{2}$

therefore z = $\sqrt{2}$